Show generated passwords with colors
This commit is contained in:
parent
62db5da62f
commit
30ae32ec5f
3 changed files with 18 additions and 15 deletions
|
|
@ -23,14 +23,15 @@ class FillPasswordTableViewCell: ContentTableViewCell {
|
|||
}
|
||||
|
||||
@IBAction func generatePassword(_ sender: UIButton) {
|
||||
contentTextField.text = Utils.randomString(length: 16)
|
||||
let plainPassword = Utils.randomString(length: 16)
|
||||
contentTextField.attributedText = Utils.attributedPassword(plainPassword: plainPassword)
|
||||
}
|
||||
|
||||
override func getContent() -> String? {
|
||||
return contentTextField.text
|
||||
return contentTextField.attributedText?.string
|
||||
}
|
||||
|
||||
override func setContent(content: String) {
|
||||
contentTextField.text = content
|
||||
contentTextField.attributedText = Utils.attributedPassword(plainPassword: content)
|
||||
}
|
||||
}
|
||||
|
|
|
|||
|
|
@ -71,18 +71,7 @@ class LabelTableViewCell: UITableViewCell {
|
|||
|
||||
func revealPassword(_ sender: Any?) {
|
||||
if let plainPassword = cellData?.content {
|
||||
let attributePassword = NSMutableAttributedString.init(string: plainPassword)
|
||||
// draw all digits in the password into red
|
||||
// draw all punctuation characters in the password into blue
|
||||
for (index, element) in plainPassword.unicodeScalars.enumerated() {
|
||||
if NSCharacterSet.decimalDigits.contains(element) {
|
||||
attributePassword.addAttribute(NSForegroundColorAttributeName, value: Globals.red, range: NSRange(location: index, length: 1))
|
||||
} else if NSCharacterSet.punctuationCharacters.contains(element) {
|
||||
attributePassword.addAttribute(NSForegroundColorAttributeName, value: Globals.blue, range: NSRange(location: index, length: 1))
|
||||
}
|
||||
}
|
||||
// set contentLabel
|
||||
contentLabel.attributedText = attributePassword
|
||||
contentLabel.attributedText = Utils.attributedPassword(plainPassword: plainPassword)
|
||||
} else {
|
||||
contentLabel.text = ""
|
||||
}
|
||||
|
|
|
|||
Loading…
Add table
Add a link
Reference in a new issue